Thread: [HELP] Check if "Just do it" is in users input

Like Adak said there a lot of ways to do this program

So here's my approach
Thanks for all your help!

Code:

/************************************************************************** * exp7a.c
 *
 * NES113 - 4C
 * ACOSTA, Arbyn M.
 *
 * A program that will accept a user input of not more than 50 characters
 * and find set of letters that will produce the string “just do it” then
 * output the string “just do it” if the letters in the entered string can
 * be used to produce the desired string
 *************************************************************************/


#include <ctype.h>
#include <stdio.h>
#include <string.h>


int
main(void)
{
    char string[51], just_do_it[] = "JUSTDOIT";
    int correct = 0;


    fgets(string, 51, stdin);


    // capitalize the input of the user
    for (int i = 0, end = strlen(string); i < end; i++)
        string[i] = toupper(string[i]);


    // iterate over the input for input checking
    for (int i = 0, end = strlen(string); i < end; i++)
    {
        for (int j = 0; j < 8; j++)
        {
            // checks if a letter matched and its not a space
            if (string[i] == just_do_it[j] && just_do_it[j] != ' ' && string[i] != ' ')
            {
                correct++;


                // replace the letter with space to avoid redudancy
                just_do_it[j] = ' ';
                break;
            }
        }
    }


    if (correct == 8)
        printf("\nJust do it\n");
    else
        printf("\nThe word just do it cannot be found on the sentence you type.\n");
    return 0;
}